Base | Representation |
---|---|
bin | 1100011011010100011000… |
… | …0000000111100000011011 |
3 | 1210101012210101201011201122 |
4 | 3012311012000013200123 |
5 | 3242330234120420233 |
6 | 45020524230435455 |
7 | 2610103260445151 |
oct | 306650600074033 |
9 | 53335711634648 |
10 | 13663465404443 |
11 | 4398709018a68 |
12 | 16480a2b02b8b |
13 | 7815c7cb877a |
14 | 35345b0b33d1 |
15 | 18a6410cdd98 |
hex | c6d4600781b |
13663465404443 has 2 divisors, whose sum is σ = 13663465404444. Its totient is φ = 13663465404442.
The previous prime is 13663465404389. The next prime is 13663465404473. The reversal of 13663465404443 is 34440456436631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13663465404443 - 214 = 13663465388059 is a prime.
It is not a weakly prime, because it can be changed into another prime (13663465404473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6831732702221 + 6831732702222.
It is an arithmetic number, because the mean of its divisors is an integer number (6831732702222).
Almost surely, 213663465404443 is an apocalyptic number.
13663465404443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13663465404443 is an equidigital number, since it uses as much as digits as its factorization.
13663465404443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29859840, while the sum is 53.
The spelling of 13663465404443 in words is "thirteen trillion, six hundred sixty-three billion, four hundred sixty-five million, four hundred four thousand, four hundred forty-three".
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