Base | Representation |
---|---|
bin | 111111101000011011… |
… | …1010001011000100111 |
3 | 111001201020120120001122 |
4 | 1333100313101120213 |
5 | 4214323410324411 |
6 | 142435243444155 |
7 | 12605160664505 |
oct | 1772067213047 |
9 | 431636516048 |
10 | 136648136231 |
11 | 52a523462a2 |
12 | 2259722665b |
13 | cb69321159 |
14 | 68843d1675 |
15 | 384b8269db |
hex | 1fd0dd1627 |
136648136231 has 2 divisors, whose sum is σ = 136648136232. Its totient is φ = 136648136230.
The previous prime is 136648136179. The next prime is 136648136257. The reversal of 136648136231 is 132631846631.
It is a strong prime.
It is an emirp because it is prime and its reverse (132631846631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136648136231 - 214 = 136648119847 is a prime.
It is a super-2 number, since 2×1366481362312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136648139231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68324068115 + 68324068116.
It is an arithmetic number, because the mean of its divisors is an integer number (68324068116).
Almost surely, 2136648136231 is an apocalyptic number.
136648136231 is a deficient number, since it is larger than the sum of its proper divisors (1).
136648136231 is an equidigital number, since it uses as much as digits as its factorization.
136648136231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 373248, while the sum is 44.
The spelling of 136648136231 in words is "one hundred thirty-six billion, six hundred forty-eight million, one hundred thirty-six thousand, two hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •