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13665025993 is a prime number
BaseRepresentation
bin11001011100111111…
…11011111111001001
31022021100011020121211
430232133323333021
5210441221312433
610135544533121
7662426542633
oct145637737711
938240136554
1013665025993
115882607313
1227944811a1
13139a0b70c8
14938bdba53
1554ea168cd
hex32e7fbfc9

13665025993 has 2 divisors, whose sum is σ = 13665025994. Its totient is φ = 13665025992.

The previous prime is 13665025991. The next prime is 13665026017. The reversal of 13665025993 is 39952056631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13551986569 + 113039424 = 116413^2 + 10632^2 .

It is a cyclic number.

It is not a de Polignac number, because 13665025993 - 21 = 13665025991 is a prime.

Together with 13665025991, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13665025991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6832512996 + 6832512997.

It is an arithmetic number, because the mean of its divisors is an integer number (6832512997).

Almost surely, 213665025993 is an apocalyptic number.

It is an amenable number.

13665025993 is a deficient number, since it is larger than the sum of its proper divisors (1).

13665025993 is an equidigital number, since it uses as much as digits as its factorization.

13665025993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1312200, while the sum is 49.

The spelling of 13665025993 in words is "thirteen billion, six hundred sixty-five million, twenty-five thousand, nine hundred ninety-three".