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13674677142019 is a prime number
BaseRepresentation
bin1100011011111110001001…
…0001100000001000000011
31210102021201202120110022111
43012333202101200020003
53243021214322021034
645030020541120151
72610651150602545
oct306774221401003
953367652513274
1013674677142019
1143a2441826393
12164a2b1859057
13782693a49b0a
14353c0213d695
1518aa9a545364
hexc6fe2460203

13674677142019 has 2 divisors, whose sum is σ = 13674677142020. Its totient is φ = 13674677142018.

The previous prime is 13674677142017. The next prime is 13674677142023. The reversal of 13674677142019 is 91024177647631.

It is a weak prime.

It is an emirp because it is prime and its reverse (91024177647631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13674677142019 - 21 = 13674677142017 is a prime.

It is a super-2 number, since 2×136746771420192 (a number of 27 digits) contains 22 as substring.

Together with 13674677142017, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13674677142017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6837338571009 + 6837338571010.

It is an arithmetic number, because the mean of its divisors is an integer number (6837338571010).

Almost surely, 213674677142019 is an apocalyptic number.

13674677142019 is a deficient number, since it is larger than the sum of its proper divisors (1).

13674677142019 is an equidigital number, since it uses as much as digits as its factorization.

13674677142019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10668672, while the sum is 58.

The spelling of 13674677142019 in words is "thirteen trillion, six hundred seventy-four billion, six hundred seventy-seven million, one hundred forty-two thousand, nineteen".