Base | Representation |
---|---|
bin | 11111000101111110111111… |
… | …010100111011010000110111 |
3 | 122221012020101120111110012212 |
4 | 133011332333110323100313 |
5 | 120411010334424434343 |
6 | 1202502220415004035 |
7 | 40542624114145163 |
oct | 3705767724732067 |
9 | 587166346443185 |
10 | 136750673671223 |
11 | 3a6336a92284a7 |
12 | 13407243b0961b |
13 | 5b3c6c1573051 |
14 | 25aaaa7265ca3 |
15 | 10c22eb19ec18 |
hex | 7c5fbf53b437 |
136750673671223 has 2 divisors, whose sum is σ = 136750673671224. Its totient is φ = 136750673671222.
The previous prime is 136750673671201. The next prime is 136750673671307. The reversal of 136750673671223 is 322176376057631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 136750673671223 - 28 = 136750673670967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136750673676223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68375336835611 + 68375336835612.
It is an arithmetic number, because the mean of its divisors is an integer number (68375336835612).
Almost surely, 2136750673671223 is an apocalyptic number.
136750673671223 is a deficient number, since it is larger than the sum of its proper divisors (1).
136750673671223 is an equidigital number, since it uses as much as digits as its factorization.
136750673671223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40007520, while the sum is 59.
The spelling of 136750673671223 in words is "one hundred thirty-six trillion, seven hundred fifty billion, six hundred seventy-three million, six hundred seventy-one thousand, two hundred twenty-three".
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