Base | Representation |
---|---|
bin | 11001011110011111… |
… | …01010010010100001 |
3 | 1022022012200211200212 |
4 | 30233033222102201 |
5 | 211002422131132 |
6 | 10141113023505 |
7 | 662641066316 |
oct | 145717522241 |
9 | 38265624625 |
10 | 13677536417 |
11 | 5889681606 |
12 | 27986b4b95 |
13 | 139c87751c |
14 | 93a736d0d |
15 | 550b885b2 |
hex | 32f3ea4a1 |
13677536417 has 2 divisors, whose sum is σ = 13677536418. Its totient is φ = 13677536416.
The previous prime is 13677536387. The next prime is 13677536437. The reversal of 13677536417 is 71463577631.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13677536401 + 16 = 116951^2 + 4^2 .
It is an emirp because it is prime and its reverse (71463577631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13677536417 - 28 = 13677536161 is a prime.
It is a super-2 number, since 2×136775364172 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13677536437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6838768208 + 6838768209.
It is an arithmetic number, because the mean of its divisors is an integer number (6838768209).
Almost surely, 213677536417 is an apocalyptic number.
It is an amenable number.
13677536417 is a deficient number, since it is larger than the sum of its proper divisors (1).
13677536417 is an equidigital number, since it uses as much as digits as its factorization.
13677536417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2222640, while the sum is 50.
The spelling of 13677536417 in words is "thirteen billion, six hundred seventy-seven million, five hundred thirty-six thousand, four hundred seventeen".
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