Base | Representation |
---|---|
bin | 11111000110011000110100… |
… | …101100010010100101111011 |
3 | 122221021212222202001200122001 |
4 | 133012120310230102211323 |
5 | 120411434142102043024 |
6 | 1202523045115041431 |
7 | 40544625366453505 |
oct | 3706306454224573 |
9 | 587255882050561 |
10 | 136778412534139 |
11 | 3a6444430847a2 |
12 | 134106a5740277 |
13 | 5b421c234c0bc |
14 | 25ac17927ad75 |
15 | 10c2dc1532244 |
hex | 7c6634b1297b |
136778412534139 has 2 divisors, whose sum is σ = 136778412534140. Its totient is φ = 136778412534138.
The previous prime is 136778412534059. The next prime is 136778412534143. The reversal of 136778412534139 is 931435214877631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136778412534139 - 213 = 136778412525947 is a prime.
It is a super-2 number, since 2×1367784125341392 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (136778412564139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68389206267069 + 68389206267070.
It is an arithmetic number, because the mean of its divisors is an integer number (68389206267070).
Almost surely, 2136778412534139 is an apocalyptic number.
136778412534139 is a deficient number, since it is larger than the sum of its proper divisors (1).
136778412534139 is an equidigital number, since it uses as much as digits as its factorization.
136778412534139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 91445760, while the sum is 64.
The spelling of 136778412534139 in words is "one hundred thirty-six trillion, seven hundred seventy-eight billion, four hundred twelve million, five hundred thirty-four thousand, one hundred thirty-nine".
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