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1367936421697 is a prime number
BaseRepresentation
bin10011111001111111010…
…111010100111101000001
311211202212211201020211201
4103321333113110331001
5134403013210443242
62524231000541201
7200554511506636
oct23717727247501
94752784636751
101367936421697
114881584a234a
121a1147181801
139bcc3b66b31
144a2cc0b618d
15258b32b54b7
hex13e7f5d4f41

1367936421697 has 2 divisors, whose sum is σ = 1367936421698. Its totient is φ = 1367936421696.

The previous prime is 1367936421671. The next prime is 1367936421713. The reversal of 1367936421697 is 7961246397631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1284031188801 + 83905232896 = 1133151^2 + 289664^2 .

It is a cyclic number.

It is not a de Polignac number, because 1367936421697 - 223 = 1367928033089 is a prime.

It is a super-2 number, since 2×13679364216972 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1367936451697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 683968210848 + 683968210849.

It is an arithmetic number, because the mean of its divisors is an integer number (683968210849).

Almost surely, 21367936421697 is an apocalyptic number.

It is an amenable number.

1367936421697 is a deficient number, since it is larger than the sum of its proper divisors (1).

1367936421697 is an equidigital number, since it uses as much as digits as its factorization.

1367936421697 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 61725888, while the sum is 64.

The spelling of 1367936421697 in words is "one trillion, three hundred sixty-seven billion, nine hundred thirty-six million, four hundred twenty-one thousand, six hundred ninety-seven".