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1367936438041 is a prime number
BaseRepresentation
bin10011111001111111010…
…111011000111100011001
311211202212211202002021001
4103321333113120330121
5134403013212004131
62524231001145001
7200554511605405
oct23717727307431
94752784662231
101367936438041
11488158503658
121a114718b161
139bcc3b713c4
144a2cc0bc105
15258b32ba261
hex13e7f5d8f19

1367936438041 has 2 divisors, whose sum is σ = 1367936438042. Its totient is φ = 1367936438040.

The previous prime is 1367936437999. The next prime is 1367936438081. The reversal of 1367936438041 is 1408346397631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 930260250000 + 437676188041 = 964500^2 + 661571^2 .

It is a cyclic number.

It is not a de Polignac number, because 1367936438041 - 229 = 1367399567129 is a prime.

It is not a weakly prime, because it can be changed into another prime (1367936438081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 683968219020 + 683968219021.

It is an arithmetic number, because the mean of its divisors is an integer number (683968219021).

Almost surely, 21367936438041 is an apocalyptic number.

It is an amenable number.

1367936438041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1367936438041 is an equidigital number, since it uses as much as digits as its factorization.

1367936438041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7838208, while the sum is 55.

The spelling of 1367936438041 in words is "one trillion, three hundred sixty-seven billion, nine hundred thirty-six million, four hundred thirty-eight thousand, forty-one".