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1367936438081 is a prime number
BaseRepresentation
bin10011111001111111010…
…111011000111101000001
311211202212211202002022112
4103321333113120331001
5134403013212004311
62524231001145105
7200554511605463
oct23717727307501
94752784662275
101367936438081
11488158503694
121a114718b195
139bcc3b71425
144a2cc0bc133
15258b32ba28b
hex13e7f5d8f41

1367936438081 has 2 divisors, whose sum is σ = 1367936438082. Its totient is φ = 1367936438080.

The previous prime is 1367936438041. The next prime is 1367936438123. The reversal of 1367936438081 is 1808346397631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1002419461681 + 365516976400 = 1001209^2 + 604580^2 .

It is a cyclic number.

It is not a de Polignac number, because 1367936438081 - 214 = 1367936421697 is a prime.

It is a super-2 number, since 2×13679364380812 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1367936438081.

It is not a weakly prime, because it can be changed into another prime (1367936438041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 683968219040 + 683968219041.

It is an arithmetic number, because the mean of its divisors is an integer number (683968219041).

Almost surely, 21367936438081 is an apocalyptic number.

It is an amenable number.

1367936438081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1367936438081 is an equidigital number, since it uses as much as digits as its factorization.

1367936438081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15676416, while the sum is 59.

The spelling of 1367936438081 in words is "one trillion, three hundred sixty-seven billion, nine hundred thirty-six million, four hundred thirty-eight thousand, eighty-one".