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1368025943 is a prime number
BaseRepresentation
bin101000110001010…
…0110101101010111
310112100011220210112
41101202212231113
510300203312233
6343425313235
745621012554
oct12142465527
93470156715
101368025943
11642240159
1232219581b
1318a56510b
14cd98ba2b
158017b048
hex518a6b57

1368025943 has 2 divisors, whose sum is σ = 1368025944. Its totient is φ = 1368025942.

The previous prime is 1368025933. The next prime is 1368025949. The reversal of 1368025943 is 3495208631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1368025943 - 24 = 1368025927 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1368025943.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1368025949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684012971 + 684012972.

It is an arithmetic number, because the mean of its divisors is an integer number (684012972).

Almost surely, 21368025943 is an apocalyptic number.

1368025943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1368025943 is an equidigital number, since it uses as much as digits as its factorization.

1368025943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 41.

The square root of 1368025943 is about 36986.8347253452. The cubic root of 1368025943 is about 1110.1068379160.

The spelling of 1368025943 in words is "one billion, three hundred sixty-eight million, twenty-five thousand, nine hundred forty-three".