Search a number
-
+
136805842944 = 215372383
BaseRepresentation
bin111111101101001000…
…0111000000000000000
3111002010020022220000000
41333122100320000000
54220134243433234
6142503040000000
712612114323031
oct1773220700000
9432106286000
10136805842944
1153023371721
1222620000000
13cb92bbab34
14689b324a88
15385a5c9899
hex1fda438000

136805842944 has 512 divisors, whose sum is σ = 433348876800. Its totient is φ = 43093721088.

The previous prime is 136805842919. The next prime is 136805842973. The reversal of 136805842944 is 449248508631.

136805842944 is a `hidden beast` number, since 1 + 36 + 8 + 0 + 584 + 29 + 4 + 4 = 666.

It is a tau number, because it is divible by the number of its divisors (512).

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1648263127 + ... + 1648263209.

It is an arithmetic number, because the mean of its divisors is an integer number (846384525).

Almost surely, 2136805842944 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 136805842944, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (216674438400).

136805842944 is an abundant number, since it is smaller than the sum of its proper divisors (296543033856).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

136805842944 is an frugal number, since it uses more digits than its factorization.

136805842944 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 157 (or 111 counting only the distinct ones).

The product of its (nonzero) digits is 6635520, while the sum is 54.

The spelling of 136805842944 in words is "one hundred thirty-six billion, eight hundred five million, eight hundred forty-two thousand, nine hundred forty-four".