Base | Representation |
---|---|
bin | 1100011100010101010110… |
… | …1100100110101100010011 |
3 | 1210102212211001011000100001 |
4 | 3013011111230212230103 |
5 | 3243122000100001224 |
6 | 45032531142510431 |
7 | 2611261445222056 |
oct | 307052554465423 |
9 | 53385731130301 |
10 | 13680908593939 |
11 | 43a504a271454 |
12 | 164b550735417 |
13 | 783147a62982 |
14 | 35423399aa9d |
15 | 18ad1264b544 |
hex | c7155b26b13 |
13680908593939 has 2 divisors, whose sum is σ = 13680908593940. Its totient is φ = 13680908593938.
The previous prime is 13680908593903. The next prime is 13680908593993. The reversal of 13680908593939 is 93939580908631.
13680908593939 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (13680908593993) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13680908593939 - 219 = 13680908069651 is a prime.
It is not a weakly prime, because it can be changed into another prime (13680908593999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6840454296969 + 6840454296970.
It is an arithmetic number, because the mean of its divisors is an integer number (6840454296970).
Almost surely, 213680908593939 is an apocalyptic number.
13680908593939 is a deficient number, since it is larger than the sum of its proper divisors (1).
13680908593939 is an equidigital number, since it uses as much as digits as its factorization.
13680908593939 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 340122240, while the sum is 73.
The spelling of 13680908593939 in words is "thirteen trillion, six hundred eighty billion, nine hundred eight million, five hundred ninety-three thousand, nine hundred thirty-nine".
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