Base | Representation |
---|---|
bin | 10011111010001010010… |
… | …001011001110100011111 |
3 | 11211210100121001102202212 |
4 | 103322022101121310133 |
5 | 134403402032340033 |
6 | 2524301055111035 |
7 | 200562163115162 |
oct | 23721221316437 |
9 | 4753317042685 |
10 | 1368119418143 |
11 | 488241821285 |
12 | 1a119851247b |
13 | 9c022a4985a |
14 | 4a30850dad9 |
15 | 258c43b1748 |
hex | 13e8a459d1f |
1368119418143 has 2 divisors, whose sum is σ = 1368119418144. Its totient is φ = 1368119418142.
The previous prime is 1368119418121. The next prime is 1368119418217. The reversal of 1368119418143 is 3418149118631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1368119418143 - 226 = 1368052309279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1368119418091 and 1368119418100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1368119618143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684059709071 + 684059709072.
It is an arithmetic number, because the mean of its divisors is an integer number (684059709072).
Almost surely, 21368119418143 is an apocalyptic number.
1368119418143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1368119418143 is an equidigital number, since it uses as much as digits as its factorization.
1368119418143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 497664, while the sum is 50.
The spelling of 1368119418143 in words is "one trillion, three hundred sixty-eight billion, one hundred nineteen million, four hundred eighteen thousand, one hundred forty-three".
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