Base | Representation |
---|---|
bin | 111111101101011000… |
… | …0100011011110010111 |
3 | 111002010210221210200101 |
4 | 1333122300203132113 |
5 | 4220143410204404 |
6 | 142503533554531 |
7 | 12612245031352 |
oct | 1773260433627 |
9 | 432123853611 |
10 | 136814147479 |
11 | 53028023a79 |
12 | 22622945a47 |
13 | cb94837a69 |
14 | 689c487299 |
15 | 385b1ba2a4 |
hex | 1fdac23797 |
136814147479 has 2 divisors, whose sum is σ = 136814147480. Its totient is φ = 136814147478.
The previous prime is 136814147473. The next prime is 136814147537. The reversal of 136814147479 is 974741418631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 136814147479 - 23 = 136814147471 is a prime.
It is a super-2 number, since 2×1368141474792 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136814147471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68407073739 + 68407073740.
It is an arithmetic number, because the mean of its divisors is an integer number (68407073740).
Almost surely, 2136814147479 is an apocalyptic number.
136814147479 is a deficient number, since it is larger than the sum of its proper divisors (1).
136814147479 is an equidigital number, since it uses as much as digits as its factorization.
136814147479 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4064256, while the sum is 55.
The spelling of 136814147479 in words is "one hundred thirty-six billion, eight hundred fourteen million, one hundred forty-seven thousand, four hundred seventy-nine".
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