Base | Representation |
---|---|
bin | 1100011100011010010110… |
… | …1000110000001011001011 |
3 | 1210110000021111210101100001 |
4 | 3013012211220300023023 |
5 | 3243132221414331413 |
6 | 45033312212423431 |
7 | 2611336622032402 |
oct | 307064550601313 |
9 | 53400244711301 |
10 | 13682249761483 |
11 | 43a5678327486 |
12 | 164b865917b77 |
13 | 7832cc882a34 |
14 | 35431db56639 |
15 | 18ad9026e4dd |
hex | c71a5a302cb |
13682249761483 has 2 divisors, whose sum is σ = 13682249761484. Its totient is φ = 13682249761482.
The previous prime is 13682249761417. The next prime is 13682249761493. The reversal of 13682249761483 is 38416794228631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13682249761483 - 233 = 13673659826891 is a prime.
It is a super-2 number, since 2×136822497614832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13682249761493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6841124880741 + 6841124880742.
It is an arithmetic number, because the mean of its divisors is an integer number (6841124880742).
Almost surely, 213682249761483 is an apocalyptic number.
13682249761483 is a deficient number, since it is larger than the sum of its proper divisors (1).
13682249761483 is an equidigital number, since it uses as much as digits as its factorization.
13682249761483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 83607552, while the sum is 64.
The spelling of 13682249761483 in words is "thirteen trillion, six hundred eighty-two billion, two hundred forty-nine million, seven hundred sixty-one thousand, four hundred eighty-three".
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