Base | Representation |
---|---|
bin | 111111110001101010… |
… | …1011111111010110100 |
3 | 111002111211201210210100 |
4 | 1333203111133322310 |
5 | 4220442230044342 |
6 | 142530114154100 |
7 | 12615643134222 |
oct | 1774325377264 |
9 | 432454653710 |
10 | 136958049972 |
11 | 530a1281057 |
12 | 22662b82930 |
13 | cbb85b0473 |
14 | 68b3625b12 |
15 | 3868b42e4c |
hex | 1fe355feb4 |
136958049972 has 36 divisors (see below), whose sum is σ = 357367244416. Its totient is φ = 44180015760.
The previous prime is 136958049959. The next prime is 136958049989. The reversal of 136958049972 is 279940859631.
136958049972 is a `hidden beast` number, since 1 + 3 + 6 + 9 + 580 + 49 + 9 + 7 + 2 = 666.
It is a tau number, because it is divible by the number of its divisors (36).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 61360018 + ... + 61362249.
It is a 1-persistent number, because it is pandigital, but 2⋅136958049972 = 273916099944 is not.
Almost surely, 2136958049972 is an apocalyptic number.
136958049972 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
136958049972 is an abundant number, since it is smaller than the sum of its proper divisors (220409194444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136958049972 is a wasteful number, since it uses less digits than its factorization.
136958049972 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 122722308 (or 122722303 counting only the distinct ones).
The product of its (nonzero) digits is 29393280, while the sum is 63.
The spelling of 136958049972 in words is "one hundred thirty-six billion, nine hundred fifty-eight million, forty-nine thousand, nine hundred seventy-two".
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