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13699063841 is a prime number
BaseRepresentation
bin11001100001000011…
…10010000000100001
31022100201012112202212
430300201302000201
5211023430020331
610143202251505
7663322056431
oct146041620041
938321175685
1013699063841
11589a845471
1227a3956b95
1313a4173c48
1493d53c2c1
155529dbd2b
hex330872021

13699063841 has 2 divisors, whose sum is σ = 13699063842. Its totient is φ = 13699063840.

The previous prime is 13699063823. The next prime is 13699063843. The reversal of 13699063841 is 14836099631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12604777441 + 1094286400 = 112271^2 + 33080^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13699063841 is a prime.

It is a Sophie Germain prime.

Together with 13699063843, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13699063841.

It is not a weakly prime, because it can be changed into another prime (13699063843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6849531920 + 6849531921.

It is an arithmetic number, because the mean of its divisors is an integer number (6849531921).

Almost surely, 213699063841 is an apocalyptic number.

It is an amenable number.

13699063841 is a deficient number, since it is larger than the sum of its proper divisors (1).

13699063841 is an equidigital number, since it uses as much as digits as its factorization.

13699063841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 839808, while the sum is 50.

The spelling of 13699063841 in words is "thirteen billion, six hundred ninety-nine million, sixty-three thousand, eight hundred forty-one".