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1370021544053 is a prime number
BaseRepresentation
bin10011111011111011101…
…001011100000001110101
311211222021011020102222122
4103323323221130001311
5134421301003402203
62525213524205325
7200660260660601
oct23737351340165
94758234212878
101370021544053
11489028499668
121a1629539845
139c266b45c46
144a448dac501
152598638e538
hex13efba5c075

1370021544053 has 2 divisors, whose sum is σ = 1370021544054. Its totient is φ = 1370021544052.

The previous prime is 1370021544011. The next prime is 1370021544091. The reversal of 1370021544053 is 3504451200731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 888264780484 + 481756763569 = 942478^2 + 694087^2 .

It is a cyclic number.

It is not a de Polignac number, because 1370021544053 - 238 = 1095143637109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1370021543053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685010772026 + 685010772027.

It is an arithmetic number, because the mean of its divisors is an integer number (685010772027).

Almost surely, 21370021544053 is an apocalyptic number.

It is an amenable number.

1370021544053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1370021544053 is an equidigital number, since it uses as much as digits as its factorization.

1370021544053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 35.

Adding to 1370021544053 its reverse (3504451200731), we get a palindrome (4874472744784).

The spelling of 1370021544053 in words is "one trillion, three hundred seventy billion, twenty-one million, five hundred forty-four thousand, fifty-three".