Base | Representation |
---|---|
bin | 10011111011111100111… |
… | …101000001001011111111 |
3 | 11211222022200110121001211 |
4 | 103323330331001023333 |
5 | 134421322111013312 |
6 | 2525220025545251 |
7 | 200660645133601 |
oct | 23737475011377 |
9 | 4758280417054 |
10 | 1370043454207 |
11 | 4890398a402a |
12 | 1a1634945227 |
13 | 9c26b54792c |
14 | 4a44bc73171 |
15 | 2598826b3a7 |
hex | 13efcf412ff |
1370043454207 has 2 divisors, whose sum is σ = 1370043454208. Its totient is φ = 1370043454206.
The previous prime is 1370043454201. The next prime is 1370043454217. The reversal of 1370043454207 is 7024543400731.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1370043454207 - 211 = 1370043452159 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1370043454207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1370043454201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685021727103 + 685021727104.
It is an arithmetic number, because the mean of its divisors is an integer number (685021727104).
Almost surely, 21370043454207 is an apocalyptic number.
1370043454207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1370043454207 is an equidigital number, since it uses as much as digits as its factorization.
1370043454207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 282240, while the sum is 40.
Adding to 1370043454207 its reverse (7024543400731), we get a palindrome (8394586854938).
The spelling of 1370043454207 in words is "one trillion, three hundred seventy billion, forty-three million, four hundred fifty-four thousand, two hundred seven".
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