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1370478398407 is a prime number
BaseRepresentation
bin10011111100010110111…
…000001100101111000111
311212000102222220001100021
4103330112320030233013
5134423214432222112
62525331124200011
7201004506115516
oct23742670145707
94760388801307
101370478398407
11489242367048
121a1736539007
139c30a6a2771
144a48d93267d
15259b1533907
hex13f16e0cbc7

1370478398407 has 2 divisors, whose sum is σ = 1370478398408. Its totient is φ = 1370478398406.

The previous prime is 1370478398389. The next prime is 1370478398411. The reversal of 1370478398407 is 7048938740731.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1370478398407 - 215 = 1370478365639 is a prime.

It is a super-2 number, since 2×13704783984072 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1370478398447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685239199203 + 685239199204.

It is an arithmetic number, because the mean of its divisors is an integer number (685239199204).

Almost surely, 21370478398407 is an apocalyptic number.

1370478398407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1370478398407 is an equidigital number, since it uses as much as digits as its factorization.

1370478398407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28449792, while the sum is 61.

The spelling of 1370478398407 in words is "one trillion, three hundred seventy billion, four hundred seventy-eight million, three hundred ninety-eight thousand, four hundred seven".