Base | Representation |
---|---|
bin | 10011111100110110101… |
… | …010110001100011100001 |
3 | 11212001211011111010100011 |
4 | 103330312222301203201 |
5 | 134430313002000423 |
6 | 2525500055524521 |
7 | 201023643410665 |
oct | 23746652614341 |
9 | 4761734433304 |
10 | 1371011750113 |
11 | 489496433085 |
12 | 1a1865089741 |
13 | 9c3940342a5 |
14 | 4a5006ca8a5 |
15 | 259e3288b0d |
hex | 13f36ab18e1 |
1371011750113 has 2 divisors, whose sum is σ = 1371011750114. Its totient is φ = 1371011750112.
The previous prime is 1371011750107. The next prime is 1371011750117. The reversal of 1371011750113 is 3110571101731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 994393879249 + 376617870864 = 997193^2 + 613692^2 .
It is a cyclic number.
It is not a de Polignac number, because 1371011750113 - 217 = 1371011619041 is a prime.
It is a super-2 number, since 2×13710117501132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1371011750117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685505875056 + 685505875057.
It is an arithmetic number, because the mean of its divisors is an integer number (685505875057).
Almost surely, 21371011750113 is an apocalyptic number.
It is an amenable number.
1371011750113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371011750113 is an equidigital number, since it uses as much as digits as its factorization.
1371011750113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2205, while the sum is 31.
Adding to 1371011750113 its reverse (3110571101731), we get a palindrome (4481582851844).
The spelling of 1371011750113 in words is "one trillion, three hundred seventy-one billion, eleven million, seven hundred fifty thousand, one hundred thirteen".
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