Base | Representation |
---|---|
bin | 10011111100110110101… |
… | …010110001100011011011 |
3 | 11212001211011111010022221 |
4 | 103330312222301203123 |
5 | 134430313002000412 |
6 | 2525500055524511 |
7 | 201023643410656 |
oct | 23746652614333 |
9 | 4761734433287 |
10 | 1371011750107 |
11 | 48949643307a |
12 | 1a1865089737 |
13 | 9c39403429c |
14 | 4a5006ca89d |
15 | 259e3288b07 |
hex | 13f36ab18db |
1371011750107 has 2 divisors, whose sum is σ = 1371011750108. Its totient is φ = 1371011750106.
The previous prime is 1371011750099. The next prime is 1371011750113. The reversal of 1371011750107 is 7010571101731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1371011750107 - 23 = 1371011750099 is a prime.
It is a super-3 number, since 3×13710117501073 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1371011750117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685505875053 + 685505875054.
It is an arithmetic number, because the mean of its divisors is an integer number (685505875054).
Almost surely, 21371011750107 is an apocalyptic number.
1371011750107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371011750107 is an equidigital number, since it uses as much as digits as its factorization.
1371011750107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5145, while the sum is 34.
Adding to 1371011750107 its reverse (7010571101731), we get a palindrome (8381582851838).
The spelling of 1371011750107 in words is "one trillion, three hundred seventy-one billion, eleven million, seven hundred fifty thousand, one hundred seven".
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