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1371104355779 is a prime number
BaseRepresentation
bin10011111100111100001…
…100000010010111000011
311212002001121201222102122
4103330330030002113003
5134431010203341104
62525513204434455
7201026146505234
oct23747414022703
94762047658378
101371104355779
11489533734094
121a18900a8a2b
139c3aa289242
144a50cb1508b
15259eb47c6be
hex13f3c3025c3

1371104355779 has 2 divisors, whose sum is σ = 1371104355780. Its totient is φ = 1371104355778.

The previous prime is 1371104355629. The next prime is 1371104355809. The reversal of 1371104355779 is 9775534011731.

It is a strong prime.

It is an emirp because it is prime and its reverse (9775534011731) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1371104355779 - 240 = 271592728003 is a prime.

It is a super-2 number, since 2×13711043557792 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1371104355779.

It is not a weakly prime, because it can be changed into another prime (1371104351779) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685552177889 + 685552177890.

It is an arithmetic number, because the mean of its divisors is an integer number (685552177890).

Almost surely, 21371104355779 is an apocalyptic number.

1371104355779 is a deficient number, since it is larger than the sum of its proper divisors (1).

1371104355779 is an equidigital number, since it uses as much as digits as its factorization.

1371104355779 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2778300, while the sum is 53.

The spelling of 1371104355779 in words is "one trillion, three hundred seventy-one billion, one hundred four million, three hundred fifty-five thousand, seven hundred seventy-nine".