Base | Representation |
---|---|
bin | 1100011110000110100111… |
… | …0110010110010100111101 |
3 | 1210112210021212111211011221 |
4 | 3013201221312112110331 |
5 | 3244121231213314431 |
6 | 45054520045513341 |
7 | 2613416036314333 |
oct | 307415166262475 |
9 | 53483255454157 |
10 | 13711311463741 |
11 | 4406a30960531 |
12 | 1655416572851 |
13 | 785c81732668 |
14 | 3558b9715b53 |
15 | 18b9e1804111 |
hex | c7869d9653d |
13711311463741 has 2 divisors, whose sum is σ = 13711311463742. Its totient is φ = 13711311463740.
The previous prime is 13711311463723. The next prime is 13711311463753. The reversal of 13711311463741 is 14736411311731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9920950260516 + 3790361203225 = 3149754^2 + 1946885^2 .
It is a cyclic number.
It is not a de Polignac number, because 13711311463741 - 223 = 13711303075133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13711311463541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6855655731870 + 6855655731871.
It is an arithmetic number, because the mean of its divisors is an integer number (6855655731871).
Almost surely, 213711311463741 is an apocalyptic number.
It is an amenable number.
13711311463741 is a deficient number, since it is larger than the sum of its proper divisors (1).
13711311463741 is an equidigital number, since it uses as much as digits as its factorization.
13711311463741 is an evil number, because the sum of its binary digits is even.
The product of its digits is 127008, while the sum is 43.
The spelling of 13711311463741 in words is "thirteen trillion, seven hundred eleven billion, three hundred eleven million, four hundred sixty-three thousand, seven hundred forty-one".
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