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137113127 is a prime number
BaseRepresentation
bin10000010110000…
…10111000100111
3100120000001211222
420023002320213
5240100110002
621334450555
73253304504
oct1013027047
9316001758
10137113127
1170440138
1239b03a5b
1322539338
14142d24ab
15c0861a2
hex82c2e27

137113127 has 2 divisors, whose sum is σ = 137113128. Its totient is φ = 137113126.

The previous prime is 137113103. The next prime is 137113201. The reversal of 137113127 is 721311731.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 137113127 - 210 = 137112103 is a prime.

It is a super-3 number, since 3×1371131273 (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 137113096 and 137113105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137113727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68556563 + 68556564.

It is an arithmetic number, because the mean of its divisors is an integer number (68556564).

Almost surely, 2137113127 is an apocalyptic number.

137113127 is a deficient number, since it is larger than the sum of its proper divisors (1).

137113127 is an equidigital number, since it uses as much as digits as its factorization.

137113127 is an evil number, because the sum of its binary digits is even.

The product of its digits is 882, while the sum is 26.

The square root of 137113127 is about 11709.5314594564. The cubic root of 137113127 is about 515.6555287073.

Adding to 137113127 its reverse (721311731), we get a palindrome (858424858).

The spelling of 137113127 in words is "one hundred thirty-seven million, one hundred thirteen thousand, one hundred twenty-seven".