Base | Representation |
---|---|
bin | 10011111100111110010… |
… | …111110111001011101011 |
3 | 11212002011011201012210010 |
4 | 103330332113313023223 |
5 | 134431044044311110 |
6 | 2525520554223003 |
7 | 201030103200300 |
oct | 23747627671353 |
9 | 4762134635703 |
10 | 1371141010155 |
11 | 48955239a064 |
12 | 1a18a0424a63 |
13 | 9c3b4a51017 |
14 | 4a5139370a7 |
15 | 259ee7bd020 |
hex | 13f3e5f72eb |
1371141010155 has 48 divisors (see below), whose sum is σ = 2552324878080. Its totient is φ = 626727826368.
The previous prime is 1371141010147. The next prime is 1371141010241. The reversal of 1371141010155 is 5510101411731.
It is a happy number.
It is not a de Polignac number, because 1371141010155 - 23 = 1371141010147 is a prime.
It is a super-3 number, since 3×13711410101553 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5888536 + ... + 6116954.
It is an arithmetic number, because the mean of its divisors is an integer number (53173434960).
Almost surely, 21371141010155 is an apocalyptic number.
1371141010155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1371141010155 is a deficient number, since it is larger than the sum of its proper divisors (1181183867925).
1371141010155 is a wasteful number, since it uses less digits than its factorization.
1371141010155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 236608 (or 236601 counting only the distinct ones).
The product of its (nonzero) digits is 2100, while the sum is 30.
Adding to 1371141010155 its reverse (5510101411731), we get a palindrome (6881242421886).
The spelling of 1371141010155 in words is "one trillion, three hundred seventy-one billion, one hundred forty-one million, ten thousand, one hundred fifty-five".
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