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1371165661447 is a prime number
BaseRepresentation
bin10011111100111111110…
…101111001100100000111
311212002012220002121222221
4103330333311321210013
5134431121402131242
62525523234433211
7201030522551041
oct23747765714407
94762186077887
101371165661447
114895652a6a2a
121a18a8732807
139c3b9ba259a
144a516d12a91
1525a01a3c167
hex13f3fd79907

1371165661447 has 2 divisors, whose sum is σ = 1371165661448. Its totient is φ = 1371165661446.

The previous prime is 1371165661391. The next prime is 1371165661517. The reversal of 1371165661447 is 7441665611731.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1371165661447 - 219 = 1371165137159 is a prime.

It is a super-2 number, since 2×13711656614472 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1371165661394 and 1371165661403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1371165661147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685582830723 + 685582830724.

It is an arithmetic number, because the mean of its divisors is an integer number (685582830724).

Almost surely, 21371165661447 is an apocalyptic number.

1371165661447 is a deficient number, since it is larger than the sum of its proper divisors (1).

1371165661447 is an equidigital number, since it uses as much as digits as its factorization.

1371165661447 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2540160, while the sum is 52.

The spelling of 1371165661447 in words is "one trillion, three hundred seventy-one billion, one hundred sixty-five million, six hundred sixty-one thousand, four hundred forty-seven".