Base | Representation |
---|---|
bin | 10011111101001011001… |
… | …010001111011100110111 |
3 | 11212002201010101122000001 |
4 | 103331023022033130313 |
5 | 134432014004341401 |
6 | 2525554140332131 |
7 | 201035316534433 |
oct | 23751312173467 |
9 | 4762633348001 |
10 | 1371355543351 |
11 | 4896524a9022 |
12 | 1a1940244047 |
13 | 9c41a326341 |
14 | 4a53421d9c3 |
15 | 25a13548601 |
hex | 13f4b28f737 |
1371355543351 has 2 divisors, whose sum is σ = 1371355543352. Its totient is φ = 1371355543350.
The previous prime is 1371355543309. The next prime is 1371355543379. The reversal of 1371355543351 is 1533455531731.
It is a strong prime.
It is an emirp because it is prime and its reverse (1533455531731) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1371355543351 - 29 = 1371355542839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1371355543301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685677771675 + 685677771676.
It is an arithmetic number, because the mean of its divisors is an integer number (685677771676).
Almost surely, 21371355543351 is an apocalyptic number.
1371355543351 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371355543351 is an equidigital number, since it uses as much as digits as its factorization.
1371355543351 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1417500, while the sum is 46.
The spelling of 1371355543351 in words is "one trillion, three hundred seventy-one billion, three hundred fifty-five million, five hundred forty-three thousand, three hundred fifty-one".
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