Base | Representation |
---|---|
bin | 10011111101001101111… |
… | …001111100110000000101 |
3 | 11212002211100001202110202 |
4 | 103331031321330300011 |
5 | 134432112302312401 |
6 | 2530002503500245 |
7 | 201036416204354 |
oct | 23751571746005 |
9 | 4762740052422 |
10 | 1371401604101 |
11 | 4896764a9161 |
12 | 1a1953757685 |
13 | 9c426a32719 |
14 | 4a53a3ad99b |
15 | 25a175e606b |
hex | 13f4de7cc05 |
1371401604101 has 2 divisors, whose sum is σ = 1371401604102. Its totient is φ = 1371401604100.
The previous prime is 1371401604073. The next prime is 1371401604109. The reversal of 1371401604101 is 1014061041731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1185812102500 + 185589501601 = 1088950^2 + 430801^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1371401604101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1371401604109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685700802050 + 685700802051.
It is an arithmetic number, because the mean of its divisors is an integer number (685700802051).
Almost surely, 21371401604101 is an apocalyptic number.
It is an amenable number.
1371401604101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371401604101 is an equidigital number, since it uses as much as digits as its factorization.
1371401604101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 1371401604101 its reverse (1014061041731), we get a palindrome (2385462645832).
The spelling of 1371401604101 in words is "one trillion, three hundred seventy-one billion, four hundred one million, six hundred four thousand, one hundred one".
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