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137160511493 is a prime number
BaseRepresentation
bin111111110111101100…
…1110101000000000101
3111010000221200220210012
41333233121311000011
54221401042331433
6143002145440005
712623652053105
oct1775731650005
9433027626705
10137160511493
1153195595425
12226ba940005
13cc1b519c95
1468d2489205
15387b7d6848
hex1fef675005

137160511493 has 2 divisors, whose sum is σ = 137160511494. Its totient is φ = 137160511492.

The previous prime is 137160511441. The next prime is 137160511513. The reversal of 137160511493 is 394115061731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134851997284 + 2308514209 = 367222^2 + 48047^2 .

It is a cyclic number.

It is not a de Polignac number, because 137160511493 - 232 = 132865544197 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 137160511493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137160513493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68580255746 + 68580255747.

It is an arithmetic number, because the mean of its divisors is an integer number (68580255747).

Almost surely, 2137160511493 is an apocalyptic number.

It is an amenable number.

137160511493 is a deficient number, since it is larger than the sum of its proper divisors (1).

137160511493 is an equidigital number, since it uses as much as digits as its factorization.

137160511493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 68040, while the sum is 41.

The spelling of 137160511493 in words is "one hundred thirty-seven billion, one hundred sixty million, five hundred eleven thousand, four hundred ninety-three".