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137160702226783 is a prime number
BaseRepresentation
bin11111001011111100110110…
…111011101111000101011111
3122222122102202011120020012101
4133023330312323233011133
5120434220104232224113
61203414431241545531
740614351031312414
oct3713746673570537
9588572664506171
10137160702226783
113a7815886a9044
12134727b57a52a7
135b6c277789221
1425c28832a210b
1510ccce81e72dd
hex7cbf36eef15f

137160702226783 has 2 divisors, whose sum is σ = 137160702226784. Its totient is φ = 137160702226782.

The previous prime is 137160702226481. The next prime is 137160702226789. The reversal of 137160702226783 is 387622207061731.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-137160702226783 is a prime.

It is a super-3 number, since 3×1371607022267833 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137160702226789) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68580351113391 + 68580351113392.

It is an arithmetic number, because the mean of its divisors is an integer number (68580351113392).

Almost surely, 2137160702226783 is an apocalyptic number.

137160702226783 is a deficient number, since it is larger than the sum of its proper divisors (1).

137160702226783 is an equidigital number, since it uses as much as digits as its factorization.

137160702226783 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7112448, while the sum is 55.

The spelling of 137160702226783 in words is "one hundred thirty-seven trillion, one hundred sixty billion, seven hundred two million, two hundred twenty-six thousand, seven hundred eighty-three".