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1371901365353 is a prime number
BaseRepresentation
bin10011111101101011101…
…100011000110001101001
311212011010011110021000202
4103331223230120301221
5134434123222142403
62530124235241545
7201054665125301
oct23755354306151
94764104407022
101371901365353
11489902612192
121a1a72ba92b5
139c4a6432c3c
144a586902601
1525a46413688
hex13f6bb18c69

1371901365353 has 2 divisors, whose sum is σ = 1371901365354. Its totient is φ = 1371901365352.

The previous prime is 1371901365319. The next prime is 1371901365383. The reversal of 1371901365353 is 3535631091731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 706384778089 + 665516587264 = 840467^2 + 815792^2 .

It is a cyclic number.

It is not a de Polignac number, because 1371901365353 - 232 = 1367606398057 is a prime.

It is a super-2 number, since 2×13719013653532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1371901365298 and 1371901365307.

It is not a weakly prime, because it can be changed into another prime (1371901365383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685950682676 + 685950682677.

It is an arithmetic number, because the mean of its divisors is an integer number (685950682677).

Almost surely, 21371901365353 is an apocalyptic number.

It is an amenable number.

1371901365353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1371901365353 is an equidigital number, since it uses as much as digits as its factorization.

1371901365353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 765450, while the sum is 47.

The spelling of 1371901365353 in words is "one trillion, three hundred seventy-one billion, nine hundred one million, three hundred sixty-five thousand, three hundred fifty-three".