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13720433 is a prime number
BaseRepresentation
bin110100010101…
…101101110001
3221211001220012
4310111231301
512003023213
61210024305
7224423156
oct64255561
927731805
1013720433
117821401
124718095
132ac50cc
141b7222d
1513104a8
hexd15b71

13720433 has 2 divisors, whose sum is σ = 13720434. Its totient is φ = 13720432.

The previous prime is 13720417. The next prime is 13720439. The reversal of 13720433 is 33402731.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9591409 + 4129024 = 3097^2 + 2032^2 .

It is a cyclic number.

It is not a de Polignac number, because 13720433 - 24 = 13720417 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13720399 and 13720408.

It is not a weakly prime, because it can be changed into another prime (13720439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6860216 + 6860217.

It is an arithmetic number, because the mean of its divisors is an integer number (6860217).

Almost surely, 213720433 is an apocalyptic number.

It is an amenable number.

13720433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13720433 is an equidigital number, since it uses as much as digits as its factorization.

13720433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 23.

The square root of 13720433 is about 3704.1102845353. The cubic root of 13720433 is about 239.3991509422.

The spelling of 13720433 in words is "thirteen million, seven hundred twenty thousand, four hundred thirty-three".