Base | Representation |
---|---|
bin | 10011111111010001111… |
… | …001101001111111111001 |
3 | 11212022112200001210220202 |
4 | 103333101321221333321 |
5 | 140001131211313201 |
6 | 2531010332331545 |
7 | 201145326241352 |
oct | 23772171517771 |
9 | 4768480053822 |
10 | 1373616119801 |
11 | 48a602542622 |
12 | 1a2271313bb5 |
13 | 9c6ba777143 |
14 | 4a6aa548d29 |
15 | 25ae6c2dc6b |
hex | 13fd1e69ff9 |
1373616119801 has 2 divisors, whose sum is σ = 1373616119802. Its totient is φ = 1373616119800.
The previous prime is 1373616119797. The next prime is 1373616119857. The reversal of 1373616119801 is 1089116163731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1355780784400 + 17835335401 = 1164380^2 + 133549^2 .
It is an emirp because it is prime and its reverse (1089116163731) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1373616119801 - 22 = 1373616119797 is a prime.
It is not a weakly prime, because it can be changed into another prime (1373616119401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 686808059900 + 686808059901.
It is an arithmetic number, because the mean of its divisors is an integer number (686808059901).
Almost surely, 21373616119801 is an apocalyptic number.
It is an amenable number.
1373616119801 is a deficient number, since it is larger than the sum of its proper divisors (1).
1373616119801 is an equidigital number, since it uses as much as digits as its factorization.
1373616119801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 163296, while the sum is 47.
The spelling of 1373616119801 in words is "one trillion, three hundred seventy-three billion, six hundred sixteen million, one hundred nineteen thousand, eight hundred one".
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