Base | Representation |
---|---|
bin | 11111001111001011110000… |
… | …100010101001010111101001 |
3 | 200000102200011200202020212201 |
4 | 133033023300202221113221 |
5 | 121001340044020402131 |
6 | 1204104451524140201 |
7 | 40636404221332126 |
oct | 3717136042512751 |
9 | 600380150666781 |
10 | 137382859544041 |
11 | 3a85781a715691 |
12 | 134a9875837661 |
13 | 5b871c03bb9c7 |
14 | 25cd519d9574d |
15 | 10d399b9c2761 |
hex | 7cf2f08a95e9 |
137382859544041 has 2 divisors, whose sum is σ = 137382859544042. Its totient is φ = 137382859544040.
The previous prime is 137382859544009. The next prime is 137382859544101. The reversal of 137382859544041 is 140445958283731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115437382384041 + 21945477160000 = 10744179^2 + 4684600^2 .
It is a cyclic number.
It is not a de Polignac number, because 137382859544041 - 25 = 137382859544009 is a prime.
It is not a weakly prime, because it can be changed into another prime (137382859544741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68691429772020 + 68691429772021.
It is an arithmetic number, because the mean of its divisors is an integer number (68691429772021).
Almost surely, 2137382859544041 is an apocalyptic number.
It is an amenable number.
137382859544041 is a deficient number, since it is larger than the sum of its proper divisors (1).
137382859544041 is an equidigital number, since it uses as much as digits as its factorization.
137382859544041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116121600, while the sum is 64.
The spelling of 137382859544041 in words is "one hundred thirty-seven trillion, three hundred eighty-two billion, eight hundred fifty-nine million, five hundred forty-four thousand, forty-one".
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