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137383264013 is a prime number
BaseRepresentation
bin111111111110010101…
…1100011111100001101
3111010121110211220210112
41333330223203330031
54222330103422023
6143040224045405
712632325322262
oct1777453437415
9433543756715
10137383264013
115329a2a8716
1222761463865
13cc5570c4c8
146913cb1269
153891137478
hex1ffcae3f0d

137383264013 has 2 divisors, whose sum is σ = 137383264014. Its totient is φ = 137383264012.

The previous prime is 137383263977. The next prime is 137383264019. The reversal of 137383264013 is 310462383731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117472078564 + 19911185449 = 342742^2 + 141107^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-137383264013 is a prime.

It is a super-2 number, since 2×1373832640132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137383264019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68691632006 + 68691632007.

It is an arithmetic number, because the mean of its divisors is an integer number (68691632007).

Almost surely, 2137383264013 is an apocalyptic number.

It is an amenable number.

137383264013 is a deficient number, since it is larger than the sum of its proper divisors (1).

137383264013 is an equidigital number, since it uses as much as digits as its factorization.

137383264013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 217728, while the sum is 41.

The spelling of 137383264013 in words is "one hundred thirty-seven billion, three hundred eighty-three million, two hundred sixty-four thousand, thirteen".