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137396471 is a prime number
BaseRepresentation
bin10000011000010…
…00000011110111
3100120112110112012
420030020003313
5240133141341
621344514435
73255564542
oct1014100367
9316473465
10137396471
1170614003
123a01ba1b
13226082b4
1414367859
15c0e00eb
hex83080f7

137396471 has 2 divisors, whose sum is σ = 137396472. Its totient is φ = 137396470.

The previous prime is 137396419. The next prime is 137396477. The reversal of 137396471 is 174693731.

It is a strong prime.

It is an emirp because it is prime and its reverse (174693731) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 137396471 - 26 = 137396407 is a prime.

It is a super-3 number, since 3×1373964713 (a number of 25 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137396477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68698235 + 68698236.

It is an arithmetic number, because the mean of its divisors is an integer number (68698236).

Almost surely, 2137396471 is an apocalyptic number.

137396471 is a deficient number, since it is larger than the sum of its proper divisors (1).

137396471 is an equidigital number, since it uses as much as digits as its factorization.

137396471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 95256, while the sum is 41.

The square root of 137396471 is about 11721.6240768931. The cubic root of 137396471 is about 516.0104846837.

The spelling of 137396471 in words is "one hundred thirty-seven million, three hundred ninety-six thousand, four hundred seventy-one".