137507390112853 has 2 divisors, whose sum is σ = 137507390112854. Its totient is φ = 137507390112852.

The previous prime is 137507390112779. The next prime is 137507390112941. The reversal of 137507390112853 is 358211093705731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127527489939249 + 9979900173604 = 11292807^2 + 3159098^2 .

It is a cyclic number.

It is not a de Polignac number, because 137507390112853 - 2⁴⁵ = 102323018024021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 137507390112794 and 137507390112803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137507390212853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68753695056426 + 68753695056427.

It is an arithmetic number, because the mean of its divisors is an integer number (68753695056427).

Almost surely, 2^{137507390112853} is an apocalyptic number.

It is an amenable number.

137507390112853 is a deficient number, since it is larger than the sum of its proper divisors (1).

137507390112853 is an equidigital number, since it uses as much as digits as its factorization.

137507390112853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4762800, while the sum is 55.

The spelling of 137507390112853 in words is "one hundred thirty-seven trillion, five hundred seven billion, three hundred ninety million, one hundred twelve thousand, eight hundred fifty-three".