Base | Representation |
---|---|
bin | 10100000001000011001… |
… | …111100111010101010001 |
3 | 11212111110012020011112222 |
4 | 110001003033213111101 |
5 | 140014030012421312 |
6 | 2531523142030425 |
7 | 201243416356244 |
oct | 24010317472521 |
9 | 4774405204488 |
10 | 1375517701457 |
11 | 490398979009 |
12 | 1a2702118415 |
13 | 9c9317128a3 |
14 | 4a80ad0525b |
15 | 25ba8b50672 |
hex | 140433e7551 |
1375517701457 has 2 divisors, whose sum is σ = 1375517701458. Its totient is φ = 1375517701456.
The previous prime is 1375517701423. The next prime is 1375517701469. The reversal of 1375517701457 is 7541077155731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1051108855696 + 324408845761 = 1025236^2 + 569569^2 .
It is a cyclic number.
It is not a de Polignac number, because 1375517701457 - 218 = 1375517439313 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1375517701399 and 1375517701408.
It is not a weakly prime, because it can be changed into another prime (1375517701057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 687758850728 + 687758850729.
It is an arithmetic number, because the mean of its divisors is an integer number (687758850729).
Almost surely, 21375517701457 is an apocalyptic number.
It is an amenable number.
1375517701457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1375517701457 is an equidigital number, since it uses as much as digits as its factorization.
1375517701457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3601500, while the sum is 53.
The spelling of 1375517701457 in words is "one trillion, three hundred seventy-five billion, five hundred seventeen million, seven hundred one thousand, four hundred fifty-seven".
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