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1376142450257 is a prime number
BaseRepresentation
bin10100000001101000011…
…110110101111001010001
311212120001201210200210102
4110001220132311321101
5140021314431402012
62532105140342145
7201265043553311
oct24015036657121
94776051720712
101376142450257
114906895a0033
121a28573a4955
139ca00c95233
144a869c91441
1525be390b2c2
hex140687b5e51

1376142450257 has 2 divisors, whose sum is σ = 1376142450258. Its totient is φ = 1376142450256.

The previous prime is 1376142450253. The next prime is 1376142450269. The reversal of 1376142450257 is 7520542416731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1376137801921 + 4648336 = 1173089^2 + 2156^2 .

It is a cyclic number.

It is not a de Polignac number, because 1376142450257 - 22 = 1376142450253 is a prime.

It is not a weakly prime, because it can be changed into another prime (1376142450251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688071225128 + 688071225129.

It is an arithmetic number, because the mean of its divisors is an integer number (688071225129).

Almost surely, 21376142450257 is an apocalyptic number.

It is an amenable number.

1376142450257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1376142450257 is an equidigital number, since it uses as much as digits as its factorization.

1376142450257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1411200, while the sum is 47.

Adding to 1376142450257 its reverse (7520542416731), we get a palindrome (8896684866988).

The spelling of 1376142450257 in words is "one trillion, three hundred seventy-six billion, one hundred forty-two million, four hundred fifty thousand, two hundred fifty-seven".