Base | Representation |
---|---|
bin | 11111010010101001010000… |
… | …111111111000011111100111 |
3 | 200001021102002021110012112121 |
4 | 133102221100333320133213 |
5 | 121014234143430202213 |
6 | 1204410024404330411 |
7 | 40662524156463241 |
oct | 3722512077703747 |
9 | 601242067405477 |
10 | 137620701022183 |
11 | 3a93967aa65465 |
12 | 135279923a3a07 |
13 | 5ba3765522362 |
14 | 25dac3dac3091 |
15 | 10d9c6c1a688d |
hex | 7d2a50ff87e7 |
137620701022183 has 2 divisors, whose sum is σ = 137620701022184. Its totient is φ = 137620701022182.
The previous prime is 137620701022159. The next prime is 137620701022303. The reversal of 137620701022183 is 381220107026731.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-137620701022183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (137620701022583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68810350511091 + 68810350511092.
It is an arithmetic number, because the mean of its divisors is an integer number (68810350511092).
Almost surely, 2137620701022183 is an apocalyptic number.
137620701022183 is a deficient number, since it is larger than the sum of its proper divisors (1).
137620701022183 is an equidigital number, since it uses as much as digits as its factorization.
137620701022183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 169344, while the sum is 43.
The spelling of 137620701022183 in words is "one hundred thirty-seven trillion, six hundred twenty billion, seven hundred one million, twenty-two thousand, one hundred eighty-three".
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