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1376948500219 is a prime number
BaseRepresentation
bin10100000010011000100…
…001101011011011111011
311212122010220112021110201
4110002120201223123323
5140024442304001334
62532321133023031
7201324032065225
oct24023041533373
94778126467421
101376948500219
11490a62593326
121a2a41324a77
139cacbc85a86
144a904d53415
1525c3e57ac14
hex1409886b6fb

1376948500219 has 2 divisors, whose sum is σ = 1376948500220. Its totient is φ = 1376948500218.

The previous prime is 1376948500163. The next prime is 1376948500237. The reversal of 1376948500219 is 9120058496731.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1376948500219 - 213 = 1376948492027 is a prime.

It is a super-2 number, since 2×13769485002192 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1376948500219.

It is not a weakly prime, because it can be changed into another prime (1376948500289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688474250109 + 688474250110.

It is an arithmetic number, because the mean of its divisors is an integer number (688474250110).

It is a 1-persistent number, because it is pandigital, but 2⋅1376948500219 = 2753897000438 is not.

Almost surely, 21376948500219 is an apocalyptic number.

1376948500219 is a deficient number, since it is larger than the sum of its proper divisors (1).

1376948500219 is an equidigital number, since it uses as much as digits as its factorization.

1376948500219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 1376948500219 in words is "one trillion, three hundred seventy-six billion, nine hundred forty-eight million, five hundred thousand, two hundred nineteen".