Base | Representation |
---|---|
bin | 10100000010110001101… |
… | …101110101011111100111 |
3 | 11212200020100202110110012 |
4 | 110002301231311133213 |
5 | 140031324001230133 |
6 | 2532431111120435 |
7 | 201340353216551 |
oct | 24026155653747 |
9 | 4780210673405 |
10 | 1377371117543 |
11 | 49115a0a6a43 |
12 | 1a2b3a97311b |
13 | 9cb686b5bb5 |
14 | 4a9451244d1 |
15 | 25c6670ab48 |
hex | 140b1b757e7 |
1377371117543 has 2 divisors, whose sum is σ = 1377371117544. Its totient is φ = 1377371117542.
The previous prime is 1377371117483. The next prime is 1377371117659. The reversal of 1377371117543 is 3457111737731.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1377371117543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1377371117491 and 1377371117500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1377371177543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688685558771 + 688685558772.
It is an arithmetic number, because the mean of its divisors is an integer number (688685558772).
Almost surely, 21377371117543 is an apocalyptic number.
1377371117543 is a deficient number, since it is larger than the sum of its proper divisors (1).
1377371117543 is an equidigital number, since it uses as much as digits as its factorization.
1377371117543 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296540, while the sum is 50.
The spelling of 1377371117543 in words is "one trillion, three hundred seventy-seven billion, three hundred seventy-one million, one hundred seventeen thousand, five hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •