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137751265247 is a prime number
BaseRepresentation
bin1000000001001010011…
…1010111111111011111
3111011120010022022120212
42000102213113333133
54224103310441442
6143140531403035
712644414302211
oct2002247277737
9434503268525
10137751265247
1153468aa8472
122284475347b
13ccb3a2910b
14694ab065b1
1538b35c9a82
hex20129d7fdf

137751265247 has 2 divisors, whose sum is σ = 137751265248. Its totient is φ = 137751265246.

The previous prime is 137751265163. The next prime is 137751265273. The reversal of 137751265247 is 742562157731.

It is a strong prime.

It is an emirp because it is prime and its reverse (742562157731) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 137751265247 - 216 = 137751199711 is a prime.

It is a super-2 number, since 2×1377512652472 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 137751265195 and 137751265204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (137751265297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68875632623 + 68875632624.

It is an arithmetic number, because the mean of its divisors is an integer number (68875632624).

Almost surely, 2137751265247 is an apocalyptic number.

137751265247 is a deficient number, since it is larger than the sum of its proper divisors (1).

137751265247 is an equidigital number, since it uses as much as digits as its factorization.

137751265247 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2469600, while the sum is 50.

The spelling of 137751265247 in words is "one hundred thirty-seven billion, seven hundred fifty-one million, two hundred sixty-five thousand, two hundred forty-seven".