Base | Representation |
---|---|
bin | 10100000011010101001… |
… | …000111011100011010111 |
3 | 11212201202210001022000021 |
4 | 110003111020323203113 |
5 | 140034033122012212 |
6 | 2533010101130011 |
7 | 201361160560141 |
oct | 24032510734327 |
9 | 4781683038007 |
10 | 1377965422807 |
11 | 491434615316 |
12 | 1a30859b9907 |
13 | 9cc3186970c |
14 | 4a9a0027c91 |
15 | 25c9d9a1307 |
hex | 140d523b8d7 |
1377965422807 has 2 divisors, whose sum is σ = 1377965422808. Its totient is φ = 1377965422806.
The previous prime is 1377965422789. The next prime is 1377965422997. The reversal of 1377965422807 is 7082245697731.
It is a weak prime.
It is an emirp because it is prime and its reverse (7082245697731) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1377965422807 - 27 = 1377965422679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1377965482807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688982711403 + 688982711404.
It is an arithmetic number, because the mean of its divisors is an integer number (688982711404).
It is a 2-persistent number, because it is pandigital, and so is 2⋅1377965422807 = 2755930845614, but 3⋅1377965422807 = 4133896268421 is not.
Almost surely, 21377965422807 is an apocalyptic number.
1377965422807 is a deficient number, since it is larger than the sum of its proper divisors (1).
1377965422807 is an equidigital number, since it uses as much as digits as its factorization.
1377965422807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 35562240, while the sum is 61.
The spelling of 1377965422807 in words is "one trillion, three hundred seventy-seven billion, nine hundred sixty-five million, four hundred twenty-two thousand, eight hundred seven".
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