Base | Representation |
---|---|
bin | 11001101100100110… |
… | …11000010101100001 |
3 | 1022121110111222022001 |
4 | 30312103120111201 |
5 | 211223230430334 |
6 | 10200543044001 |
7 | 665606441212 |
oct | 146623302541 |
9 | 38543458261 |
10 | 13795951969 |
11 | 593a5009a8 |
12 | 28102a0601 |
13 | 13bb2681b7 |
14 | 94c35d409 |
15 | 55b279714 |
hex | 3364d8561 |
13795951969 has 2 divisors, whose sum is σ = 13795951970. Its totient is φ = 13795951968.
The previous prime is 13795951963. The next prime is 13795952011. The reversal of 13795951969 is 96915959731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11006527744 + 2789424225 = 104912^2 + 52815^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13795951969 is a prime.
It is a super-2 number, since 2×137959519692 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13795951969.
It is not a weakly prime, because it can be changed into another prime (13795951963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6897975984 + 6897975985.
It is an arithmetic number, because the mean of its divisors is an integer number (6897975985).
Almost surely, 213795951969 is an apocalyptic number.
It is an amenable number.
13795951969 is a deficient number, since it is larger than the sum of its proper divisors (1).
13795951969 is an equidigital number, since it uses as much as digits as its factorization.
13795951969 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20667150, while the sum is 64.
The spelling of 13795951969 in words is "thirteen billion, seven hundred ninety-five million, nine hundred fifty-one thousand, nine hundred sixty-nine".
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