Base | Representation |
---|---|
bin | 1100100011000100101100… |
… | …0111110110111110101001 |
3 | 1210211221200102021102112201 |
4 | 3020301023013312332221 |
5 | 3302021112444244103 |
6 | 45202040405540201 |
7 | 2622530654101444 |
oct | 310611307667651 |
9 | 53757612242481 |
10 | 13796695306153 |
11 | 443a166904051 |
12 | 1669a85414661 |
13 | 79103b09b136 |
14 | 359a9950c65b |
15 | 18dd3c79a51d |
hex | c8c4b1f6fa9 |
13796695306153 has 2 divisors, whose sum is σ = 13796695306154. Its totient is φ = 13796695306152.
The previous prime is 13796695306081. The next prime is 13796695306187. The reversal of 13796695306153 is 35160359669731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13541899524624 + 254795781529 = 3679932^2 + 504773^2 .
It is a cyclic number.
It is not a de Polignac number, because 13796695306153 - 29 = 13796695305641 is a prime.
It is not a weakly prime, because it can be changed into another prime (13796695306453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6898347653076 + 6898347653077.
It is an arithmetic number, because the mean of its divisors is an integer number (6898347653077).
Almost surely, 213796695306153 is an apocalyptic number.
It is an amenable number.
13796695306153 is a deficient number, since it is larger than the sum of its proper divisors (1).
13796695306153 is an equidigital number, since it uses as much as digits as its factorization.
13796695306153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82668600, while the sum is 64.
The spelling of 13796695306153 in words is "thirteen trillion, seven hundred ninety-six billion, six hundred ninety-five million, three hundred six thousand, one hundred fifty-three".
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