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13800586259413 is a prime number
BaseRepresentation
bin1100100011010011001100…
…0010101010101111010101
31210212022201120210022222201
43020310303002222233111
53302102100040300123
645203522442324501
72623026251463502
oct310646302525725
953768646708881
1013800586259413
1144408831878a8
12166a7904b9731
1379150b22c345
14359d481984a9
1518deb91805ad
hexc8d330aabd5

13800586259413 has 2 divisors, whose sum is σ = 13800586259414. Its totient is φ = 13800586259412.

The previous prime is 13800586259363. The next prime is 13800586259423. The reversal of 13800586259413 is 31495268500831.

13800586259413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8757947740689 + 5042638518724 = 2959383^2 + 2245582^2 .

It is a cyclic number.

It is not a de Polignac number, because 13800586259413 - 217 = 13800586128341 is a prime.

It is a super-2 number, since 2×138005862594132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13800586259423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6900293129706 + 6900293129707.

It is an arithmetic number, because the mean of its divisors is an integer number (6900293129707).

Almost surely, 213800586259413 is an apocalyptic number.

It is an amenable number.

13800586259413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13800586259413 is an equidigital number, since it uses as much as digits as its factorization.

13800586259413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6220800, while the sum is 55.

The spelling of 13800586259413 in words is "thirteen trillion, eight hundred billion, five hundred eighty-six million, two hundred fifty-nine thousand, four hundred thirteen".