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1380931941312 = 263371124332179
BaseRepresentation
bin10100000110000101111…
…101010011001111000000
311220000102112002001101000
4110012011331103033000
5140111122034110222
62534220312012000
7201524531554140
oct24060575231700
94800375061330
101380931941312
11492717097600
121a3773391000
13a02b532a401
144aba1dd6920
1525dc412e9ac
hex14185f533c0

1380931941312 has 672 divisors, whose sum is σ = 5113892134400. Its totient is φ = 357691023360.

The previous prime is 1380931941239. The next prime is 1380931941353. The reversal of 1380931941312 is 2131491390831.

1380931941312 is a `hidden beast` number, since 13 + 8 + 0 + 9 + 319 + 4 + 1 + 312 = 666.

It is a tau number, because it is divible by the number of its divisors (672).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 633744639 + ... + 633746817.

Almost surely, 21380931941312 is an apocalyptic number.

1380931941312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1380931941312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2556946067200).

1380931941312 is an abundant number, since it is smaller than the sum of its proper divisors (3732960193088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1380931941312 is a wasteful number, since it uses less digits than its factorization.

1380931941312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2662 (or 2635 counting only the distinct ones).

The product of its (nonzero) digits is 139968, while the sum is 45.

The spelling of 1380931941312 in words is "one trillion, three hundred eighty billion, nine hundred thirty-one million, nine hundred forty-one thousand, three hundred twelve".